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.5x^2=50
We move all terms to the left:
.5x^2-(50)=0
a = .5; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·.5·(-50)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*.5}=\frac{-10}{1} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*.5}=\frac{10}{1} =10 $
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